Решение третьего задания.
R4 + R5 = 20 + 10 = 30 Ом.
R3-5 = (60*30)/(60 + 30) = 1800/90 = 20 Ом.
R2-5 = 10 + 20 = 30 Ом.
R1-5 = (60*30)/(60 + 30) = 1800/90 = 20 Ом.
Iобщ = 100/20 = 5 A.
I1 = 100/60 = (5/3) A.
I2 = 5 - (5/3) = (10/3) A.
U3-5 = 100 - 10*(10/3) = (200/3) B.
I3 = (200/3)/60 = (10/9) A.
I4 = I5 = (10/3) - (10/9) = (20/9) A.
U5 = 10*(20/9) = (200/9) B.
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Решение третьего задания.
R4 + R5 = 20 + 10 = 30 Ом.
R3-5 = (60*30)/(60 + 30) = 1800/90 = 20 Ом.
R2-5 = 10 + 20 = 30 Ом.
R1-5 = (60*30)/(60 + 30) = 1800/90 = 20 Ом.
Iобщ = 100/20 = 5 A.
I1 = 100/60 = (5/3) A.
I2 = 5 - (5/3) = (10/3) A.
U3-5 = 100 - 10*(10/3) = (200/3) B.
I3 = (200/3)/60 = (10/9) A.
I4 = I5 = (10/3) - (10/9) = (20/9) A.
U5 = 10*(20/9) = (200/9) B.