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assasincreedl
@assasincreedl
November 2021
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беха2004
1.
а) = 4^(-1-2)=4^(-3)=1/64
б) = 5^5 : 5^2 = 5^(5-2) = 5^3 = 125
в) = 2^(-6) * 2^3 = 2^(-6+3)=2^(-3)=1/8
2.
а) = (2^2)^(-5) * (2^3)^2 = 2^(-10) * 2^6 = 2^(-10+6)=2^(-4)=1/1006
б) = (3^5 * 3^(-9))/3^(-6) = 3^(-4) / 3^(-6) = 3^2=9
в) = 14^(-6) : 14^(-5) = 14^(-6+5)=14^(-1)=1/14
г) = (1* (5^2)^(-7))/(5^3)^(-4) = 5^(-14) / 5^(-12) = 5^(-14+12) = 5^(-2)=1/25=0,4
3.
7^(3(n-2)) * 7^(n-5) * 7^2 = 7^(3n-6+n-5+2) = 7^(4n-9)
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Answers & Comments
а) = 4^(-1-2)=4^(-3)=1/64
б) = 5^5 : 5^2 = 5^(5-2) = 5^3 = 125
в) = 2^(-6) * 2^3 = 2^(-6+3)=2^(-3)=1/8
2.
а) = (2^2)^(-5) * (2^3)^2 = 2^(-10) * 2^6 = 2^(-10+6)=2^(-4)=1/1006
б) = (3^5 * 3^(-9))/3^(-6) = 3^(-4) / 3^(-6) = 3^2=9
в) = 14^(-6) : 14^(-5) = 14^(-6+5)=14^(-1)=1/14
г) = (1* (5^2)^(-7))/(5^3)^(-4) = 5^(-14) / 5^(-12) = 5^(-14+12) = 5^(-2)=1/25=0,4
3.
7^(3(n-2)) * 7^(n-5) * 7^2 = 7^(3n-6+n-5+2) = 7^(4n-9)