task/29385289
-----------------------
2sin31°cos31° / (sin38°sin66° + cos38°sin24°) =
sin62° / (sin38°sin66° +cos38°cos66°) = sin62° / cos(66°-38° ) =
sin62° / cos28° = sin62° / cos(90°- 62°) = sin62° / sin62° =1
ответ: 1.
* * * P.S. sin2α =2sinα*cosα ; cos(α - β) =cosα*cosβ +sinα*sinα*β ;
sin(90°- α) =cos α ; cos(90°- α) =sin α * * *
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
task/29385289
-----------------------
2sin31°cos31° / (sin38°sin66° + cos38°sin24°) =
sin62° / (sin38°sin66° +cos38°cos66°) = sin62° / cos(66°-38° ) =
sin62° / cos28° = sin62° / cos(90°- 62°) = sin62° / sin62° =1
ответ: 1.
* * * P.S. sin2α =2sinα*cosα ; cos(α - β) =cosα*cosβ +sinα*sinα*β ;
sin(90°- α) =cos α ; cos(90°- α) =sin α * * *
Verified answer