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polinagarres
@polinagarres
August 2022
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kirichekov
Verified answer
2cos²x-1=-1/2
2cos²x=1/2
cos²x=1/4
cosx=+-1/2
1. cosx=-1/2, x=+-(arccos(-1/2))+2πn, n∈Z. x=+-(π-arccos1/2)+2πn, n∈Z.
x₁=+-2π/3+2πn, n∈Z
2. cosx=1/2, x=+-arccos(1/2)+2πn, n∈Z
x₂=+-π/3+2πn, n∈Z
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Answers & Comments
Verified answer
2cos²x-1=-1/22cos²x=1/2
cos²x=1/4
cosx=+-1/2
1. cosx=-1/2, x=+-(arccos(-1/2))+2πn, n∈Z. x=+-(π-arccos1/2)+2πn, n∈Z.
x₁=+-2π/3+2πn, n∈Z
2. cosx=1/2, x=+-arccos(1/2)+2πn, n∈Z
x₂=+-π/3+2πn, n∈Z