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Bebo21
@Bebo21
March 2022
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Jyutjt
3(2x^2+x)=5(4x-2)
6x^2+3x=20x-10
6x^2+3x-20x+10=0
6x^2-17x+10=0
D=289-240=49
x1=(17-7)/12=10/12=5/6
x2=24/12=2
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Answers & Comments
6x^2+3x=20x-10
6x^2+3x-20x+10=0
6x^2-17x+10=0
D=289-240=49
x1=(17-7)/12=10/12=5/6
x2=24/12=2