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akaganets
@akaganets
July 2022
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Помогите с №В4. ПЛИЗ
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kirichekov
Verified answer
1+tg²α=1/cos²α
sin²α+cos²α=1, cos²α=1-sin²α
tgα=√(1/16). tgα=1/4. tgα=0,25
ответ: tgA=0,25
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Answers & Comments
Verified answer
1+tg²α=1/cos²αsin²α+cos²α=1, cos²α=1-sin²α
tgα=√(1/16). tgα=1/4. tgα=0,25
ответ: tgA=0,25