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rubaaalko16
@rubaaalko16
July 2022
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let5
AC(0-0;2-4;5+1)=(0;-2;6)
CB(1-0;3-2;0-5)=(1;1;-5)
AC-CB=(0-1;-2-1;6+5)=(-1;-3;11)
|AC-CB|=
=√1+9+121=√131
AB(-3-1;-1+1;2-0)=(-4;0;2)
CB(-3+1;-1-2;2-1)=(-2;-3;1)
AB-CB=(-4+2;0+3;2-1)=(-2;3;1)
|AB-CB|=
=√4+9+1=√14
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Answers & Comments
AC(0-0;2-4;5+1)=(0;-2;6)
CB(1-0;3-2;0-5)=(1;1;-5)
AC-CB=(0-1;-2-1;6+5)=(-1;-3;11)
|AC-CB|==√1+9+121=√131
AB(-3-1;-1+1;2-0)=(-4;0;2)
CB(-3+1;-1-2;2-1)=(-2;-3;1)
AB-CB=(-4+2;0+3;2-1)=(-2;3;1)
|AB-CB|==√4+9+1=√14