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rustamkaloveR
@rustamkaloveR
July 2022
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Alexei78
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Даноm(Na2CO3)=1250 gНайтиn(Na2CO3)-?М(Na2CO3)= 106g/moln=m/M=1250/106= 11.79molОтвет 11.79моль
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Verified answer
Даноm(Na2CO3)=1250 gНайтиn(Na2CO3)-?М(Na2CO3)= 106g/moln=m/M=1250/106= 11.79molОтвет 11.79моль