Ответ:
дано
m(ppa H3PO4) = 32.7 g
W(H3PO4) = 12%
------------------------
m(Mg) = ?
m(H3PO4)= 32.7 * 12 % / 100% = 3.924 g
3Mg+2H3PO4-->Mg3(PO4)2+3H2
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 3.924 / 98 = 0.04mol
3n(Mg) = 2n (H3PO4)
n(Mg) = 3*0.4 / 2 = 0.6 mol
M(Mg) =24 g/mol
m(Mg) = n*M = 0.6 * 24 = 14.4 g
ответ 14.4 г
Объяснение:
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Answers & Comments
Ответ:
дано
m(ppa H3PO4) = 32.7 g
W(H3PO4) = 12%
------------------------
m(Mg) = ?
m(H3PO4)= 32.7 * 12 % / 100% = 3.924 g
3Mg+2H3PO4-->Mg3(PO4)2+3H2
M(H3PO4) = 98 g/mol
n(H3PO4) = m/M = 3.924 / 98 = 0.04mol
3n(Mg) = 2n (H3PO4)
n(Mg) = 3*0.4 / 2 = 0.6 mol
M(Mg) =24 g/mol
m(Mg) = n*M = 0.6 * 24 = 14.4 g
ответ 14.4 г
Объяснение: