Помогите с задачей по Киргхофу по электротехнике.
формулы:
I1=I3+I2
E1+E2=I1×R1+I2×R2
E2=I2×R2-I3×R3
формулы:
I1=I3+I2
E1+E2=I1×R1+I2×R2
E2=I2×R2-I3×R3
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Answers & Comments
18=3*I1+3*I2, I2=6-I1,
9= 3*I2-9*I3, I3=I2/3-1= 2-I1/3-1= 1-I1/3,
I1=6-I1+1-I1/3, 7/3*I1=7, I1= 3A,
I2=3A, I3=0A