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Lestay
@Lestay
June 2022
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Помогите с задачкой по физике
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UmbertoVargas
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Закон сохранения импульса:
m1 v0 = m2 u + m1 v
u = (m1/m2) * (v0 - v) - скорость доски после соударения с пулей
закон сохранения энергии для доски:
(m2 u²)/2 = m2 g L (1 - cosα)
u² = 2 g L (1 - cosα)
(m1/m2)² * (v0 - v)² = 2 g L (1 - cosα)
m1 = (m2/(v0 - v)) * √(2 g L (1 - cosα))
m1 = (4.6/150) * sqrt(2*9.8*1.45*(1-0.996)) ≈
0.01034 кг = 10.34 г
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Answers & Comments
Verified answer
Закон сохранения импульса:m1 v0 = m2 u + m1 v
u = (m1/m2) * (v0 - v) - скорость доски после соударения с пулей
закон сохранения энергии для доски:
(m2 u²)/2 = m2 g L (1 - cosα)
u² = 2 g L (1 - cosα)
(m1/m2)² * (v0 - v)² = 2 g L (1 - cosα)
m1 = (m2/(v0 - v)) * √(2 g L (1 - cosα))
m1 = (4.6/150) * sqrt(2*9.8*1.45*(1-0.996)) ≈ 0.01034 кг = 10.34 г