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@xvv
July 2022
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помогите с заданием плачу дорого
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agasikkk
Сos²2x = понижаем степень = (1+сos4x)/2
1-2(1+cos4x)/2 = √2/2
1-1-cos4x=√2/2
cos4x=-√2/2
cos4x=+-3п/4 +2пn
x=+- 3п/16+пn/2
_____________________________
вроде так
1 votes
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agasikkk
оц
xvv
спасибо огромное)))
agasikkk
у тебя ответов нету?
xvv
нет
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Answers & Comments
1-2(1+cos4x)/2 = √2/2
1-1-cos4x=√2/2
cos4x=-√2/2
cos4x=+-3п/4 +2пn
x=+- 3п/16+пn/2
_____________________________
вроде так