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vfhbyf1
@vfhbyf1
December 2021
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помогите с заданием с логарифмами, пожалуйста
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mmb1
Verified answer
Loga b= 1/logb a
lgx+logx 10
возводим в квадрат (1) (lgx + logx 10)^2=(lgx+1/lgx)^2=lg^2 x + 1/lg^2 x + 2*lgx*1/lgx=lg^2x + logx^2 2+2
lg^2 x + log^2x 10=23 значит (1)=23+2=25
lgx + logx 10 = +-5
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Answers & Comments
Verified answer
Loga b= 1/logb algx+logx 10
возводим в квадрат (1) (lgx + logx 10)^2=(lgx+1/lgx)^2=lg^2 x + 1/lg^2 x + 2*lgx*1/lgx=lg^2x + logx^2 2+2
lg^2 x + log^2x 10=23 значит (1)=23+2=25
lgx + logx 10 = +-5