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maxturbo2006
@maxturbo2006
June 2022
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помогите с заданием во вложении
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Verified answer
107)
v1=10t
v2=6-4t
x1=5t^2
x2=6t-2t^2
v1(t=1)=10*1=10 м/с
v2(t=1)=6-4*1=2 м/с
v1(t=1,5)=10*1,5=15 м/с
v2(t=1,5)=6-4*1,5=0 м/с
x1(t=1)=5*1^2=5 м
x2(t=1)=6*1-2*1^2=4 м
x1(t=1,5)=5*1,5^2=
11,25
м
x2(t=1,5)=6*1,5-2*1,5^2=
4,5
м
109)
x1=-14+15t
x2=10t-t^2
x1=x2 при t=2
v1=15t
v2=10-2t
a) v1(t=2)=30; v2(t=2)=6
б) x1(t=4)-x2(t=4)=22
в) v2=0 при t=5; x1(t=5)=61
110)
S=(v1+v2)*t/2 = (10+16)*100/2 =
1300
м =1,3 км
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Answers & Comments
Verified answer
107)v1=10t
v2=6-4t
x1=5t^2
x2=6t-2t^2
v1(t=1)=10*1=10 м/с
v2(t=1)=6-4*1=2 м/с
v1(t=1,5)=10*1,5=15 м/с
v2(t=1,5)=6-4*1,5=0 м/с
x1(t=1)=5*1^2=5 м
x2(t=1)=6*1-2*1^2=4 м
x1(t=1,5)=5*1,5^2=11,25 м
x2(t=1,5)=6*1,5-2*1,5^2=4,5 м
109)
x1=-14+15t
x2=10t-t^2
x1=x2 при t=2
v1=15t
v2=10-2t
a) v1(t=2)=30; v2(t=2)=6
б) x1(t=4)-x2(t=4)=22
в) v2=0 при t=5; x1(t=5)=61
110)
S=(v1+v2)*t/2 = (10+16)*100/2 = 1300 м =1,3 км