ВинтЛили (x2)/(x-3)-(x-2)/(x+3)+(2x^2-10x-18)/(x^2-9)=(2(x²-5x-18))/((x-3)(x+3))
x-3≠ 0 and x+3≠0 and x²-9≠0
x≠3 and x≠-3 (x-3)(x+3)≠0
x-3≠ 0 and x+3≠0 x-3≠0 and x+3≠0
x≠3 and x≠-3 and x≠3 and x≠-3
x∈(-∞;-3)U(-3;3)U(3;+∞)

так вроде.