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Kriss1802
@Kriss1802
August 2021
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kattycats
2Ba + O2 = 2BaO реакция соединения
BaO + 2HCl = BaCl2 + H2O реакция обмена
BaO + 2H(+) + 2Cl(-) = Ba(2+) + 2Cl(-) + H2O
BaO + 2H(+) = Ba(2+) + H2O
BaCl2 + H2SO4 = BaSO4 + 2HCl реакция обмена
Ba(2+) + 2Cl(-) + 2H(+) + SO4(2-) = BaSO4 + 2H(+) + 2Cl(-)
Ba(2+) + SO4(2-) = BaSO4 (осадок)
m(Na3PO4) = nxM = 0,5x164 = 82 г
m(p-pa) = m(Na3PO4) + m(H2O) = 82 + 118 = 200 г
m(H2O) = V(H2O)xp(H2O) = 118x1 = 118 г, p(H2O) = 1 г/мл
W(Na3PO4) = [m(Na3PO4)/m(p-pa)]x100% = [82/200]x100% = 41 %
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Answers & Comments
BaO + 2HCl = BaCl2 + H2O реакция обмена
BaO + 2H(+) + 2Cl(-) = Ba(2+) + 2Cl(-) + H2O
BaO + 2H(+) = Ba(2+) + H2O
BaCl2 + H2SO4 = BaSO4 + 2HCl реакция обмена
Ba(2+) + 2Cl(-) + 2H(+) + SO4(2-) = BaSO4 + 2H(+) + 2Cl(-)
Ba(2+) + SO4(2-) = BaSO4 (осадок)
m(Na3PO4) = nxM = 0,5x164 = 82 г
m(p-pa) = m(Na3PO4) + m(H2O) = 82 + 118 = 200 г
m(H2O) = V(H2O)xp(H2O) = 118x1 = 118 г, p(H2O) = 1 г/мл
W(Na3PO4) = [m(Na3PO4)/m(p-pa)]x100% = [82/200]x100% = 41 %