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dashullya2001
@dashullya2001
July 2022
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ПОМОГИТЕ СОКРАТИТЬ ДРОБЬ!!!!! Пожалуйстаааа: 5x^2+4x-1 дробь 5x^2-6x+1 ????????
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pentV
5x²+4x-1=0
D=16-4*5*(-1)=36=6²
x_1=(-4+6)/10=0.2 x_2=(-4-6)/10=-1
(x-0.2)(x+1) в числителе
5x²-6x+1=0
D=36-4*5=16=4²
x_1=(6+4)/10=1 x_2=(6-4)/10=0.2
(x-1)(x-0.2) в знаменателе
x-0.2 сократится и останется (х+1)/(х-1)
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Answers & Comments
D=16-4*5*(-1)=36=6²
x_1=(-4+6)/10=0.2 x_2=(-4-6)/10=-1
(x-0.2)(x+1) в числителе
5x²-6x+1=0
D=36-4*5=16=4²
x_1=(6+4)/10=1 x_2=(6-4)/10=0.2
(x-1)(x-0.2) в знаменателе
x-0.2 сократится и останется (х+1)/(х-1)