Verified answer

1

(x/2 + y/3)*6 = (3x/6 + 2y/6)*6 = 3x + 2y

x = 4 y = -1

3*4 + 2*(-1) = 12 - 2 = 10

2

(x/4 - y/12)*12 = (3x/12 - y/12)*12 = 3x - y

x = -2 y = 3

3*(-3) - 3 = -9 - 3 = -12

3

(2x/3 + y/5)*3 = 2x + 3y/5

x = 1 y = 2

2*1 + 3*2/5 = 2 + 6/5 = 3 1/5 = 3.2

4

(5x/6 - 3y/8)*4 = 10x/3 - 3y/2

x = 6 y = 2

10*6/3 - 3*2/2 = 20 - 3 = 17