Sin(α - 90) - Cos(α - 180) + tg(α - 270) + Ctg(360 + α) = - Sin(90 - α) -
- Cos(180 - α) - tg(270 - α) + Ctg(360 + α) = - Cosα + Cosα - Ctgα + Ctgα = 0
=-sin(90-a)-cos(180-a)-tg(270-a)+ctg(360+a)=-cos a+cos a-ctg a+ctg a=0
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Sin(α - 90) - Cos(α - 180) + tg(α - 270) + Ctg(360 + α) = - Sin(90 - α) -
- Cos(180 - α) - tg(270 - α) + Ctg(360 + α) = - Cosα + Cosα - Ctgα + Ctgα = 0
Verified answer
=-sin(90-a)-cos(180-a)-tg(270-a)+ctg(360+a)=-cos a+cos a-ctg a+ctg a=0