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Naydvvv
@Naydvvv
September 2021
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Помогите срочно. Ирр уравнения
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isom
(√х+2)² = (3х-4)²
х+2 = 9х²-24х+16
х+2-9х²+24х-16=0
-9х²+25х-14=0
Д=625-4(-9)(-14)=625-504=121
х₁=(-25-11)/-18=-36/-18=2
х₂=(-25+11)/-18=-14/-18=7/9
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Answers & Comments
х+2 = 9х²-24х+16
х+2-9х²+24х-16=0
-9х²+25х-14=0
Д=625-4(-9)(-14)=625-504=121
х₁=(-25-11)/-18=-36/-18=2
х₂=(-25+11)/-18=-14/-18=7/9