❗ помогите срочно надо❗. Created by viktoriazanik81. matematika-ru

❗ помогите срочно надо❗...

viktoriazanik81 @viktoriazanik81

August 2022 1 15 Report

❗ помогите срочно надо❗

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Meloni12

1.° $\frac{8}{x - 4} \\ x - 4 = 0 \\ x = 4$

2.°

$\frac{24 {a}^{6} {b}^{4} }{16 {a}^{3 {b}^{7} } } = \frac{3 {a}^{3} }{2 {b}^{3} }$

$\frac{15x - 10xy}{5xy} \frac{5x(3 - 2y)}{5xy} = \frac{3 - 2y}{y}$

$\frac{ {m }^{2 } - 4}{2m - 4} = \frac{(m - 2)(m + 2)}{2(m - 2)} = \frac{m + 2}{2}$

$\frac{25 - {a}^{2} }{ {a}^{2} - 10a + 25} = \frac{(5 - a)(5 + a)}{(a - 5) {}^{2} } = - \frac{(a - 5)(5 + a)}{(a - 5) {}^{2} } = \frac{ - (5 + a)}{a - 5} = - \frac{5 + a}{a - 5}$

3.°

$\frac{x - 8}{4 {x}^{2} } - \frac{5 - 12x}{6 {x}^{3} } = \frac{3x(x - 8) - 2(5 - 12x)}{12 {x}^{3} } = \frac{3 {x}^{3} - 24x - 10 + 24x }{12 {x}^{3} } = \frac{3 {x}^{3} }{12 {x}^{3} }$

$\frac{20}{ {a}^{2} + 4a} - \frac{5}{a} = \frac{20}{a(a + 4)} - \frac{5}{a} = \frac{20 - 5(a + 4)}{a(a + 4)} = \frac{ - 5a}{a(a + 4)} = \frac{ - 5}{a + 4}$

$\frac{ {m}^{2} }{ {m}^{2} - 9} - \frac{m}{m + 3} = \frac{ {m}^{2} }{(m - 3)(m + 3)} - \frac{m}{m + 3} = \frac{ {m}^{2} - m(m - 3)}{(m - 3)(m + 3)} = \frac{ {m}^{2} {m}^{2} + 3m }{ {m}^{2} - 9} = \frac{3m}{ {m}^{2} - 9}$

$2p - \frac{14 {p}^{2} }{7p + 3} = \frac{2p(7p + 3) - 14 {p}^{2} }{7p + 3} = \frac{14 {p}^{2} + 6p - 14 {p}^{2} }{7p + 3} = \frac{6p}{7p + 3}$

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