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sabitovarm
@sabitovarm
June 2022
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Помогите срочно нужно
Найдите наибольшее значение функции
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pomoshnik09
Ответ 14 правильно?
у`=24cos x -12√3=0 cos x=√3/2 x=π/6 ∈[0 π/2] это точка максимума
у(π/6)= 24*sinπ/6-12√3*π/6+2√3π+2=24*1/2-2√3π+2√3π+2=12+2=14
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pomoshnik09
эттоне простой пример
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Answers & Comments
у`=24cos x -12√3=0 cos x=√3/2 x=π/6 ∈[0 π/2] это точка максимума
у(π/6)= 24*sinπ/6-12√3*π/6+2√3π+2=24*1/2-2√3π+2√3π+2=12+2=14