Home
О нас
Products
Services
Регистрация
Войти
Поиск
IrinaÇoban
@IrinaÇoban
November 2021
1
9
Report
помогите, срочно, очень прошу!!!!(((((
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Кулшат
1) 5π/6+π/4 =13π/12; π/3 + π/2 =5π/6; 1 +π/6 = 1 +π/6;
coosπ/6 = 1/2;
2) = (1/3 *x - π/3) =πn, n∈Z; 1/3*x =πn +π/3; x = 3πn +π; n∈Z;
=2x =2π/3 +2πn,n∈Z; x = π/3 +πn,n∈Z;
2cosx -1 =0; 2cosx = 1; cosx =1/2; x =+- π/3+2πn,n∈Z;
sinx = √2/2; x = [tex] (-1)^{n} \pi /4 + \pi n, n∈Z;
0 votes
Thanks 0
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "помогите, срочно, очень прошу!!!!(((((..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
coosπ/6 = 1/2;
2) = (1/3 *x - π/3) =πn, n∈Z; 1/3*x =πn +π/3; x = 3πn +π; n∈Z;
=2x =2π/3 +2πn,n∈Z; x = π/3 +πn,n∈Z;
2cosx -1 =0; 2cosx = 1; cosx =1/2; x =+- π/3+2πn,n∈Z;
sinx = √2/2; x = [tex] (-1)^{n} \pi /4 + \pi n, n∈Z;