1)sin(-45°)=-√2/2 , sin³(-45°)=(-√2/2)³=( -2√2)/8
ctg(-45°)=-1, cos(-45°)=√2/2
8*( -2√2)/8-√2(-1)+√2/2= -2√2+√2+√2/2=-√2+√2/2=-√2/2
2)tg(-π/4)=-1, tg²(-π/3)=( -√3)²=3 , sin(-π/2)=-1 , cos²(-π/6)=(√3/2)²=3/4
2*(-1)*3+3*(-1)+10*3/4=-6-3+7,5=-1,5
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Answers & Comments
1)sin(-45°)=-√2/2 , sin³(-45°)=(-√2/2)³=( -2√2)/8
ctg(-45°)=-1, cos(-45°)=√2/2
8*( -2√2)/8-√2(-1)+√2/2= -2√2+√2+√2/2=-√2+√2/2=-√2/2
2)tg(-π/4)=-1, tg²(-π/3)=( -√3)²=3 , sin(-π/2)=-1 , cos²(-π/6)=(√3/2)²=3/4
2*(-1)*3+3*(-1)+10*3/4=-6-3+7,5=-1,5