Ответ:
(sin130°+sin110°)/cos130°+cos110°= =(2sin120°COs10°)/(2cos120°cos10°)= =tg120=tg(90°+30°)=-cotg30°=-vЗ.
Ответ -3.
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Ответ:
(sin130°+sin110°)/cos130°+cos110°= =(2sin120°COs10°)/(2cos120°cos10°)= =tg120=tg(90°+30°)=-cotg30°=-vЗ.
Ответ -3.