помогите срочно пожалуйстааа. Created by filinasab123. matematika-ru

( а )Проверка:( б )Проверка:

помогите срочно пожалуйстааа...

filinasab123 @filinasab123

August 2022 1 9 Report

помогите срочно пожалуйстааа

Answers & Comments

ksyuwi

( а )

$\displaystyle\\7\frac{13}{39}-x=2\frac{26}{39}\\ \\ 7\frac{1}{3}-x=2\frac{2}{3}\\ \\ -x=2\frac{2}{3}-7\frac{1}{3}\\ \\ x=7\frac{1}{3}-2\frac{2}{3}\\ \\ x=6\frac{4}{3}-2\frac{2}{3}\\ \\ x=4\frac{2}{3}$

Проверка:

$\displaystyle\\7\frac{13}{39}-4\frac{2}{3}=2\frac{26}{39}\\ \\ 7\frac{1}{3}-4\frac{2}{3}=2\frac{2}{3}\\ \\6\frac{4}{3}-4\frac{2}{3}=2\frac{2}{3}\\ \\ 2\frac{2}{3}=2\frac{2}{3}$

( б )

$\displaystyle\\(\frac{5}{22} +x)-8\frac{13}{22}=4\frac{19}{22} \\\\\frac{5}{22} +x-8\frac{13}{22}=4\frac{19}{22}\\\\x=4\frac{19}{22} -\frac{5}{22} +8\frac{13}{22} \\\\x=4\frac{14}{22}+8\frac{13}{22} \\\\x=12\frac{27}{22}\\ \\x=13\frac{5}{22}$

Проверка:

$\displaystyle\\(\frac{5}{22}+13\frac{5}{22})-8\frac{13}{22}=4\frac{19}{22}\\ \\ 13\frac{10}{22}-8\frac{13}{22}=4\frac{19}{22}\\ \\ 12\frac{32}{22}-8\frac{13}{22}=4\frac{19}{22}\\ \\4 \frac{19}{22}=4\frac{19}{22}$

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