3^log(3)y=y

y-log(3)x=1

log(3)x=y-1

x=3^(y-1)

во второе

3^(y*(y-1)=3^12

y^2-y=12

y^2-y-12=0

D=49

y1=(1+7)/2=4; x1=3^(4-1)=27

y2=(1-7)/2=-3; x2=3^(-3-1)=1/81

Ответ (27;4);(1/81;-3)