Помогите срочно пожалуйста!Задание на листочке пожалуйста ребят срочно!!!. Created by qasqad7682. algebra-ru

1(x-2)(x+2)(x+3)/(x+1)²≥0x=2 x=-2 x=-3 x=-1 _ + _ _ +--------------[-3]--------[-2]----------(-1)------------[2]-----------x∈[-3;-2] U [2;∞)2{xy(x+y)=20{(x=y)-xy=1x+y=a xy=b{ab=20a-b=1⇒a=1+b(1+b)b=20b²+b-20=0b1+b2=-1 U b1*b2=-20b1=-5⇒a1=-4{x+y=-4⇒x=-4-y{xy=-5y(-4-y)=-5y²+4y-5=0y1=y2=-4 U y1*y2=-5y1=-5⇒x1=1y2=1⇒x2=-5b2=4⇒a2=5{x+y=5{x*y=4по теореме Виета х=1,у=4 или х=4,у=1 Ответ (1;-5);(-5;1);(1;4);(4;1)43x²+bx+12=0D=b²-144<0(b-12)(b+12)<0b=12 b=-12b∈(-12;12) Реклама Реклама Новые вопросы в Алгебра ДАМ 30 БАЛЛОВ!!!!!!!!!!!!!!!!!!!! определите сколько корней имеет каждое уравнение, и найдите корни если они существуют помогите срочно пожалуйста! 1. Преобразуйте уравнение (х+2)²+2х=5x(х- 2)к виду ах² + bx +c=0 и укажите старший коэффициент, второй коэффициент и свободный член. решите квадратные уравнениеСРОЧНО!!! (а+b)×(a+b) пожалуйста решите я просто дуб срочно!!! Даю 15 баллов СРОЧНО ЗАДАНИЕ НА КАТИНКЕ!!!!!!!!!!!!!!! Решить уравнение: 3 cos^2 x + 8 sos x - 3 = 0 СРОЧНО НУЖНО СДЕЛАТЬ СОР ПРЯМО СЕЙЧАС ПОЖАЛУЙСТА СОР ПО АЛГЕБРЕ 7 класс 2 четверть 1 СОР ДАЮ 15 БАЛЛОВ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! 10 класс. Объясните пожалуйста как находить значения тригонометрических функций угла альфа. Например: Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Помогите срочно пожалуйста!Задание на листочке пожалуйста ребят срочно!!!...

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December 2021 1 4 Report

Помогите срочно пожалуйста!Задание на листочке пожалуйста ребят срочно!!!

Answers & Comments

sedinalana

Verified answer

1
(x-2)(x+2)(x+3)/(x+1)²≥0
x=2 x=-2 x=-3 x=-1
_ + _ _ +
--------------[-3]--------[-2]----------(-1)------------[2]-----------
x∈[-3;-2] U [2;∞)
2
{xy(x+y)=20
{(x=y)-xy=1
x+y=a xy=b
{ab=20
a-b=1⇒a=1+b
(1+b)b=20
b²+b-20=0
b1+b2=-1 U b1*b2=-20
b1=-5⇒a1=-4
{x+y=-4⇒x=-4-y
{xy=-5
y(-4-y)=-5
y²+4y-5=0
y1=y2=-4 U y1*y2=-5
y1=-5⇒x1=1
y2=1⇒x2=-5
b2=4⇒a2=5
{x+y=5
{x*y=4
по теореме Виета х=1,у=4 или х=4,у=1
Ответ (1;-5);(-5;1);(1;4);(4;1)
4
3x²+bx+12=0
D=b²-144<0
(b-12)(b+12)<0
b=12 b=-12
b∈(-12;12)