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LPSEmma
@LPSEmma
August 2022
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Помогите срочно!!!
Пусть x^2 + y^2 = 19, xy = 3. Найти |x+y|
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nastyaermakova5
2(x+2y)+(x+2y)^2-2y^2-xy=0
(x+2y)(2-y+x+2y)=0
x+2y≠0 ОДЗ
x+y+2=0
x=-y-2
(2-y-3y-11)/(-2-y+2y)=3
-13-4y=3y-6
7y=-7
y=-1
x=-1
x-y=0
2 votes
Thanks 1
LPSEmma
Спасибо огромное, очень выручила!!
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Answers & Comments
(x+2y)(2-y+x+2y)=0
x+2y≠0 ОДЗ
x+y+2=0
x=-y-2
(2-y-3y-11)/(-2-y+2y)=3
-13-4y=3y-6
7y=-7
y=-1
x=-1
x-y=0