Ответ:
Объяснение:
1) =(6a-7-4a+3)(6a-7+4a-3)=(2a-4)(10a-10)=20(a-1)(a-2)
2) =(a^2-1)(a^2+1)-(9+a^2)^2=(a^4-1)-(9+a^2)^2
при а=1/3 (1/3)^4-1-(9+(1/3)^2)^2=1/81 - 1 -(9+1/9)^2=(1-81)/81 - 82^2/81=
(1-82^2-81)/81=((1-82)(1+82)-81)/81=(-81*83-81)/81=(-81(83+1))/81=-84
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Ответ:
Объяснение:
1) =(6a-7-4a+3)(6a-7+4a-3)=(2a-4)(10a-10)=20(a-1)(a-2)
2) =(a^2-1)(a^2+1)-(9+a^2)^2=(a^4-1)-(9+a^2)^2
при а=1/3 (1/3)^4-1-(9+(1/3)^2)^2=1/81 - 1 -(9+1/9)^2=(1-81)/81 - 82^2/81=
(1-82^2-81)/81=((1-82)(1+82)-81)/81=(-81*83-81)/81=(-81(83+1))/81=-84