Помогите срочно пжжжжжжжжжжжжжжж. Created by vadimicenko574. matematika-ru

Помогите срочно пжжжжжжжжжжжжжжж...

August 2022 2 5 Report

Помогите срочно пжжжжжжжжжжжжжжж

dinaaltyn

Пошаговое объяснение: (4x^2+6)/(x^2-9) * (x^2 -9)/(10x^2+15) =

=2/5=0,4

1 votes Thanks 1

zinaidazina

$(\frac{2x+1}{x-3} +\frac{2x-1}{x+3} )*\frac{x^2-9}{10x^{2}+15}=$

$=\frac{(2x+1)(x+3)+(2x-1)(x-3)}{(x-3)(x+3)}*\frac{x^2-9}{10x^{2}+15}=$

$=\frac{2x^2+x+6x+3+2x^2-x-6x+3}{x^{2}-9 }*\frac{x^2-9}{10x^{2}+15}=$

$=\frac{4x^2+6}{x^{2}-9 }*\frac{x^2-9}{10x^{2}+15}=$

$=\frac{2(2x^2+3)}{x^{2}-9 }*\frac{x^2-9}{5(2x^{2}+3)}=$

$=\frac{2(2x^2+3)*(x^2-9)}{(x^{2}-9)*5*(2x^{2}+3)}= \frac{2}{5}$

2 votes Thanks 1