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2katenok7272
@2katenok7272
August 2022
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Помогите срочно. Решите уравнение (4x+1)^2 =(4x-8)^2
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lidusya13
(4х+1)^2-(4х-8)^2=0;
(4х+1-4х+8)(4х+1+4х-8)=0;
9(8х-7)=0;
8х-7=0;
х=7/8
2 votes
Thanks 1
vtarani
(4х+1)^2=(4x-8)^2
16x^2+8x+1=16x^2-64x+64
1
6x^2+8x-16x^2+64x=64-1
72x=63
x=63/72
x=
0 votes
Thanks 1
5555anna
проверь удвоенное произведение во второй скобке
2katenok7272
хорошо)
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Answers & Comments
(4х+1-4х+8)(4х+1+4х-8)=0;
9(8х-7)=0;
8х-7=0;
х=7/8
16x^2+8x+1=16x^2-64x+64
16x^2+8x-16x^2+64x=64-1
72x=63
x=63/72
x=