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ksesha234
@ksesha234
July 2022
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ПОМОГИТЕ СРОЧНО УРАВНЕНИЕ РЕШИТЬ
√3 tg 3x = 1
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nafanya2014
Verified answer
Tg 3x=1/√3;
3x=atctg (1/√3)+πk, k∈Z;
3x=(π/6)+πk, k∈Z;
x=(π/18) + (π/3)k, k∈Z.
О т в е т. (π/18) + (π/3)k, k∈Z.
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Answers & Comments
Verified answer
Tg 3x=1/√3;3x=atctg (1/√3)+πk, k∈Z;
3x=(π/6)+πk, k∈Z;
x=(π/18) + (π/3)k, k∈Z.
О т в е т. (π/18) + (π/3)k, k∈Z.