помогите !!!! срочно. Created by pholina13. algebra-ru

помогите !!!! срочно...

mayli

$(\sqrt{4+\sqrt{7}}+\sqrt{4-\sqrt{7}} )^{2}=(\sqrt{4+\sqrt{7}})^{2}+2*\sqrt{4+\sqrt{7}}*\sqrt{4-\sqrt{7}}+(\sqrt{4-\sqrt{7}})^{2}=4+\sqrt{7}+2\sqrt{4^{2}-(\sqrt{7})^{2}}+4-\sqrt{7}=8+2\sqrt{16-7}=8+2\sqrt{9}=8+2*3=8+6=14\\\\Otvet:\boxed{14}$

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