Помогите, срочно) 4^log(16)81. Created by Ayiluy. matematika-ru

Помогите, срочно) 4^log(16)81...

July 2022 1 19 Report

Помогите, срочно) 4^log(16)81

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tnuriev 4^log(16, 81)=4^(4/4*log(2, 3))=4^log(2,3)=(2^log(2,3))^2=2^3=9
Свойства (если непонятно, открой св-ва логарифмов и найдешь:
log(a^x, b^y) = y/x*log(a, b)
a^log(a,b)=b

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