Помогите срочно!!!!!
1)cos2a=cos^2a-sin^2a
sin^2a+cos^2a=1
sin^2a=1-16/25, т.к п/2<a<п
sin^2a=9/25
cos2a=16/25-9/25=7/25
tga=3/5*5/4=3/4
sina=3/5
2) cos135=sqrt2/2
sin8p/3=sqrt3/2
tg7p/3=2
cos^2p/8-sin^2p/8=cos2p/8=вопрос
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Answers & Comments
1)cos2a=cos^2a-sin^2a
sin^2a+cos^2a=1
sin^2a=1-16/25, т.к п/2<a<п
sin^2a=9/25
cos2a=16/25-9/25=7/25
tga=3/5*5/4=3/4
sina=3/5
2) cos135=sqrt2/2
sin8p/3=sqrt3/2
tg7p/3=2
cos^2p/8-sin^2p/8=cos2p/8=вопрос