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nastyademina17
@nastyademina17
July 2022
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Помогите срочно!!!!!!!
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rima134
Cos2x-sinx-1/(2cosx-v3)=0 1-2sin^2x-sinx-1/(2cosx-v3)=0 -2sin^2x-sinx/(2cosx-v3)=0
-2sinx(sinx-1)=0 sinx=0 x=pi*n sinx-1=0 sinx=1 x=pi/2+2pi*m n,m (- Z
одз х не равно +-pi/6+2pi*n (cosx=v3/2)
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Answers & Comments
-2sinx(sinx-1)=0 sinx=0 x=pi*n sinx-1=0 sinx=1 x=pi/2+2pi*m n,m (- Z
одз х не равно +-pi/6+2pi*n (cosx=v3/2)