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roslavceva12
@roslavceva12
August 2022
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Помогите срочно!
Докажите, что при всех целых n значение выражения n(n-1)-(n+3)(n+2) делится на 6.
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Zeus163
Раскроем скобки:
1) n(n-1)-(n+3)(n+2)=n²-n-n²-3n-2n-6=-6n-6=-6(n+1)
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Answers & Comments
1) n(n-1)-(n+3)(n+2)=n²-n-n²-3n-2n-6=-6n-6=-6(n+1)