помогите срочно!!!!!!. Created by GreenApelsin. algebra-ru

помогите срочно!!!!!!...

July 2022 1 43 Report

помогите срочно!!!!!!

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incognita001 3) cosx=t
t^2-3t+2=0
D=1
t1=1 t2=2
cos=1 cos=2(не удовлетворяет)
2Пk
4)sin^2x-sinx=0
sin(sin-1)=0
sin=0 or sin=1
Пk П/2+2Пк

1 votes Thanks 0

incognita001 4)4-5cosx-2sin^2x=0
4-5cosx-2(1-cos^2)=0
4-5cosx-2+2cos^2x=0
2cos^2x-5cosx+2=0
cosx=t
2t^2-5t+2=0
D=3
t1=2(не удовлетворяет) t2=1/2
cos=1/2

incognita001 cosx=1/2
x=+-arccos1/2+2пk

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