Помогите срочнооо 3 и 4. Created by viktoriya7667. algebra-ru

Помогите срочнооо 3 и 4...

September 2021 1 13 Report

Помогите срочнооо 3 и 4

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армения20171 Y=2x-e^(2x)+log(2)(2x+2)

y'=2-2*e^(2x)+1/((2x+2)*ln2)*(2x+2)'=

2-2e^(2x)+1/((x+1)ln2)

4)y=xe^(x²-3x);xo=2
y'(xo)=k
y'=e^(x²-3x)+x*(x²-3x)'*e^(x²-3x)=
e^(x²-3x) (1+x(2x-3))

k=y'(2)=1/e²*(1+2)=
3/e²

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pomogiteee ochen srochnoo

kak eto delatc84b26dfd7097019ed2afc4cb14db9cc 4683

na stole stoyat 20 kruzhek s chaem prichyom v shest iz nih polozhili saharoficiant s

pomogiteee srochnooofba914939201b3870e2c86b34d2388a1 10378

pomogite pozhalujstac07b1b70ab2b7f42216205c3a03a19ec 87530

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