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linoss
@linoss
July 2022
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templeofhopes
X-x^3≠0
x(1-x^2)≠0
x(1-x)(1+x)≠0
x≠0; 1; -1
(-~;-1)u(-1;0)u(0;1)u(1;+~)
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Answers & Comments
x(1-x^2)≠0
x(1-x)(1+x)≠0
x≠0; 1; -1
(-~;-1)u(-1;0)u(0;1)u(1;+~)