ПОМОГИТЕ СРОЧНОразложить на множетели. Created by kostikovamarianna3. algebra-ru

ПОМОГИТЕ СРОЧНОразложить на множетели...

imrannurdinov1111

a)25-y²=(5-y)(5+y)

б)х²+6х+9=(х+3)²

в)4х²-4х+1=(2х-1)²

г)4у²-12у+9=(2у-3)²

д)9m²+24m+16=(3m+4)²

e)(5c-1)²-(4c-1)²=(5c-1-4c+1)(5c-1+4c-1)=c(9c-2)

1 votes Thanks 1

sebrithien

а) $\displaystyle \tt 25-y^2=\bold{(5-y)(5+y)}$

б) $\displaystyle \tt x^2+6x+9=x^2+2\cdot x\cdot3+3^2=(x+3)^2=\bold{(x+3)(x+3)}$

в) $\displaystyle \tt 4x^2-4x+1=(2x)^2-2\cdot 2x \cdot 1+1^2=(2x-1)^2=\bold{(2x-1)(2x-1)}$

г) $\displaystyle \tt 4y^2-12y+9=(2y)^2-2\cdot 2y \cdot3+3^2=(2y-3)^2=\bold{(2y-3)(2y-3)}$

д) $\displaystyle \tt 9m^2+24m+16=(3m)^2+2\cdot 3m \cdot 4+4^2=(3m+4)^2=\bold{(3m+4)(3m+4)}$

е)

$\displaystyle \tt (5c-1)^2-(4c-1)^2=(5c-1-(4c-1))(5c-1+(4c-1))=(5c-1-4c+1)(5c-1+4c-1)=\bold{c(9c-2)}$

2 votes Thanks 2