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mariel24012003
@mariel24012003
August 2022
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помогите сроооочно
номер 7
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AlfaAndOmega
Биссектриса треугольника делит третью сторону на отрезки, пропорциональные двум другим сторонам.
CB/9=AB/15; 15CB=9AB; 15/9=AB/CB 24^2 + (9x)^2 = (15x)^2; 24^2=144x^2; 24=12x; x=2; CB=9x=2*9=18; S=AC*CB/2=24*18/2=216
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Answers & Comments
CB/9=AB/15; 15CB=9AB; 15/9=AB/CB 24^2 + (9x)^2 = (15x)^2; 24^2=144x^2; 24=12x; x=2; CB=9x=2*9=18; S=AC*CB/2=24*18/2=216