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nazarkoshlatyy
@nazarkoshlatyy
July 2022
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Помогите , только 2 и 3 зад.))
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sedinalana
Verified answer
2
y`=[(4x)`*(3-2x)-(3-2x)`*4x]/(3-2x)²=(4*(3-2x)+2*4x)/(3-2x)²=
=(12-8x+8x)/(3-2x)=12/(3-2x)²
y`(1)=12/(3-2*1)²=12/(3-2)²=12/1=12
3
y`=15x²+4
y`(0)=15*0+4=4
y`(1)=15*1+4=15+4=19
y`(2)=15*4+4=60+4=64
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Answers & Comments
Verified answer
2y`=[(4x)`*(3-2x)-(3-2x)`*4x]/(3-2x)²=(4*(3-2x)+2*4x)/(3-2x)²=
=(12-8x+8x)/(3-2x)=12/(3-2x)²
y`(1)=12/(3-2*1)²=12/(3-2)²=12/1=12
3
y`=15x²+4
y`(0)=15*0+4=4
y`(1)=15*1+4=15+4=19
y`(2)=15*4+4=60+4=64