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Solncemb
@Solncemb
July 2022
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Помогите упростить выражение cos⁴x+sin²xcos²x
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kirichekov
Verified answer
Cos⁴x+sin²x*cos²x=(cos²x)²+sin²x*cosx=cos²x*cos²x+sin²x*cos²x=
=cos²x*(cos²x+sin²x)=cos²x*1=
cos²x
3 votes
Thanks 5
Solncemb
А можно подробнее узнать как Вы решили?
Solncemb
Спасибо
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Answers & Comments
Verified answer
Cos⁴x+sin²x*cos²x=(cos²x)²+sin²x*cosx=cos²x*cos²x+sin²x*cos²x==cos²x*(cos²x+sin²x)=cos²x*1=cos²x