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danil2501diukin
@danil2501diukin
December 2021
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Trofimkirillov
N°1
а)(x+2)²+(2x-1)²=x²+2*x*2+2²+(2x)²-2*2x*1+1²=x²+4x+4+4x²-4x+1=5x²+5
б)(10-7y)(7y+10)=(10-7y)(10+7y)=10²-(7y)²=100-49y²=-49y²+100
в)(2+a)(4-2a+a²)=2³+a³=8+a³=a³+8
г)(a+3)³=a³+3*a²*3+3*a*3²+3³=a³+9a²+27a+27
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danil2501diukin
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Answers & Comments
а)(x+2)²+(2x-1)²=x²+2*x*2+2²+(2x)²-2*2x*1+1²=x²+4x+4+4x²-4x+1=5x²+5
б)(10-7y)(7y+10)=(10-7y)(10+7y)=10²-(7y)²=100-49y²=-49y²+100
в)(2+a)(4-2a+a²)=2³+a³=8+a³=a³+8
г)(a+3)³=a³+3*a²*3+3*a*3²+3³=a³+9a²+27a+27