=(x³/3-x²/2+3x)]₀¹=(1/3-1/2+3)-0=-1/6+3=2 5/6
=(2x+3cosx)]⁰-π/2=3+π
=∫¹₁₎₃(9x²+6x+1)dx=(9*(x³/3)+6*(x²/2)+x)¹₁₎₃=(3x³+3x²+x)¹₁₎₃=(3+3+1)-(1/9+1/3+1/3)=7-7/9=6 2/9
=3x⁴/3-x³/10+4x+C
=(-1/7)cos7x+C
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=(x³/3-x²/2+3x)]₀¹=(1/3-1/2+3)-0=-1/6+3=2 5/6
=(2x+3cosx)]⁰-π/2=3+π
=∫¹₁₎₃(9x²+6x+1)dx=(9*(x³/3)+6*(x²/2)+x)¹₁₎₃=(3x³+3x²+x)¹₁₎₃=(3+3+1)-(1/9+1/3+1/3)=7-7/9=6 2/9
=3x⁴/3-x³/10+4x+C
=(-1/7)cos7x+C