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AkaNeko060
@AkaNeko060
November 2021
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DedushkaBake
1) (1-i)^12=((1-i)²)^6=(1-2i-1)^6=(-2i)^6=(-2)^6*i^6=64(i^4)i²=64*1*(-1)=-64
2)i+i^11+i^21=i+i*i^10+i*i^20=i+i(i²)^5+i(i²)^10=i+i(-1)^5+i(-1)^10=i-i+i=i
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Answers & Comments
2)i+i^11+i^21=i+i*i^10+i*i^20=i+i(i²)^5+i(i²)^10=i+i(-1)^5+i(-1)^10=i-i+i=i