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Zirfi228 @Zirfi228

May 2022 1 2 Report

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Universalka

Verified answer

$\frac{3^{6}*9^{-7}}{27^{-3} }=\frac{3^{6}*(3^{2})^{-7}}{(3^{3})^{-3}}=\frac{3^{6}*3^{-14}}{3^{-9}}=3^{6+(-14)-(-9)}=3^{6-14+9}=3$

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