ПОМОГИТЕЕЕ! 100 БАЛЛ ДАЮ . Created by aminokka01. algebra-ru

Объяснение:Ответ: (-3;-1), (-3;1), (3;-1), (3;1).Ответ: (-1;-5), (5;1).1. Суммируем эти уравнения:2.Разделим первое уравнение на второе:Ответ: (5;3).

ПОМОГИТЕЕЕ! 100 БАЛЛ ДАЮ ...

aminokka01 @aminokka01

November 2021 1 19 Report

ПОМОГИТЕЕЕ! 100 БАЛЛ ДАЮ

Answers & Comments

sangers1959

Verified answer

Объяснение:

$9)\ \left \{ {{x^2+y^2=10} \atop {x^4+x^2y^2=90}} \right.\ \ \ \ \left \{ {{x^2+y^2=10} \atop {x^2*(x^2+y^2)=90}} \right. \ \ \ \ \left \{ {{x^2+y^2=10} \atop {x^2*10=90\ |:10}} \right. \ \ \ \ \left \{ {{x^2+y^2=10} \atop {x^2=9}} \right.\\\left \{ {{9+y^2=10} \atop {x_1=-3\ \ x_2=3}} \right. \ \ \ \ \left \{ {{y^2=1} \atop {x=-3\ \ x=3}} \right.\ \ \ \ \left \{ {{y=-1\ \ y=1} \atop {x=-3\ \ x=3}} \right..$

Ответ: (-3;-1), (-3;1), (3;-1), (3;1).

$10)\ \left \{ {{x^3-y^3=124} \atop {x^2+xy+y^2=31}} \right. \ \ \ \ \left \{ {{(x-y)*(x^2+xy+y^2)=124} \atop {x^2+xy+y^2=31}} \right. \ \ \ \ \left \{ {{(x-y)*31=124\ |:31} \atop {x^2-2xy+2xy+xy+y^2=31}} \right. \\\left \{ {{x-y=4} \atop {(x-y)^2+3xy=31}} \right.\ \ \ \ \left \{ {{x-y=4} \atop {4^2+3xy=31}} \right. \ \ \ \ \left \{ {{x-y=4} \atop {16+3xy=31}} \right.\ \ \ \ \left \{ {{x-y=4} \atop {3xy=15\ |:3}} \right. \ \ \ \ \left \{ {{x-y=4} \atop {xy=5}} \right.$

$\left \{ {{y=x-4} \atop {x*(x-4)=5}} \right. \ \ \ \ \left \{ {{y=x-4} \atop {x^2-4x-5=0}} \right.\ \ \ \ \left \{ {{y=x-4} \atop {D=36\ \ \sqrt{D}=6 }} \right. \ \ \ \ \left \{ {{y_1=-5\ \ y_2=1} \atop {x_1=-1\ \ x_2=5}} \right..$

Ответ: (-1;-5), (5;1).

$11)\ \left \{ {{x^2y+xy^2=120} \atop {x^2y-xy^2=30}} \right..$

Суммируем эти уравнения:

$2*x^2y=150\ |:2\\x^2y=75.$

$\left \{ {{xy*(x+y)=120} \atop {xy*(x-y)=30}} \right..$

Разделим первое уравнение на второе:

$\frac{x+y}{x-y} =4\\x+y=4*(x-y)\\x+y=4x-4y\\5y=3x\ |:5\\y=0,6x\ \ \ \ \Rightarrow\\\left \{ {{y=0.6x} \atop {x^2y=75}} \right.\ \ \ \ \ \left \{ {{y=0,6x} \atop {x^2*0,6x=75}} \right. \ \ \ \ \ \left \{ {{y=0,6x} \atop {0,6*x^3=75\ |:0,6}} \right. \ \ \ \ \left \{ {{y=0,6x} \atop {x^3=125=5^3}} \right.\ \ \ \ \left \{ {{y=0,6*5=3} \atop {x=5}} \right. .$

Ответ: (5;3).

3 votes Thanks 2

Answers & Comments

Verified answer

2cos18 648ed756e877f

sin30sin15 648ec67e2a1e6

sin30sin15

pomogiteeeeeeeeevypolnite sintaksicheskij razbor predlozheniyalyudi ne mogut nadlezh

s7f09612629e402c2c55938a02e8a65ce 34173

sb4165c957dda1f0e9e0784c89ca9b445 61311

opredelite tok i napryazhenie kazhdogo rezistora

ugrafik

pozhalujsta reshite v pitone dayu 100 balzadachi1otobrazhenie nechetnyh chisel ot 50

pomogite pozhalujsta dayu 50 ballov64f2c6b8d7cea7db1257808b82398499 84896

рекомендуемые вопросы

Helpful Links

Helpful Social